The Basics Of Electromagnetic Clutches & Brakes

Front Wheel Suspension System

Engine Valve

BMW ///M Engine Under Test

Mechanical Art

Mechanical engg

WOODRUF KEYS are semicircular shaped, such that, when installed, leave a protruding tab. The keyway in the shaft is a semi-circular pocket, the mating part, a longitudinal slot. They are used to improve the concentricity of the shaft and the mating part, which is critical for high speed operation. The main advantage of the Woodruff key is that it eliminates milling a keyway near shaft shoulders, which already have stress concentrations.

 High-Efficiency Belt Drives

Belt drives are frequently used in motor systems and offer advantages such as providing flexibility with positioning of the motor, allowing speed adjustments with the use of pulleys with differing diamaters, low maintenance requirements, decreased noise levels, and high efficiency. However, the efficiency of belt drives differ based on their type and condition.

V-type belts are most commonly used and offer efficiencies between 93 to 98%. However, their efficiency drops by about 4% by age and by an additional 5–10% with poor maintenance.
Wedge or cogged belts can maintain efficiencies that are around 2% higher than ordinary V-belts
Synchronous/flat/ribbed belts offer efficiencies between 96 to 99%, and require less maintenance. Advancements with these kinds of belts have widened their application possibilities, and it is worth exploring the potential to switch over to these.

 

The articulate or jointed arm robot (or sometime called Anthropomorphic arms) closely resembles the human arm. The mechanical structure has at least three rotary joints which forms a polar coordinate system. The Figure shown an articulate robot with 6 degree of freedom. The basic three rotary joints able Arm swap, shoulder swivel and elbow rotations. Additional 3 revolute joints (Roll, Yaw, Pitch) and one prismatic joint allow the robot to point in many directions, and then reach out some radial distance.

Application area:


Arc welding
Spot welding
Assembly
cleaning/spraying
Cutting
Deburring
Die casting
Gluing/sealing
Grinding/polishing
Injection moulding
Machine tending
Material handling
Packing
Palletizing
Picking
Pre-machining
Press brake tending

Mechanical Vibration Assignmnet No 1

Assignments No – I

Date of Issue: 8^th August, 2013                                             Date of Submission: 14^th August, 2013

1.      Represent the periodic motion given in figure 1 by harmonic motion

Figure 1

2.      Find the sum of harmonic motion of equal amplitude but of slightly different frequencies. Discuss the beat phenomenon that results from this sum.

3.      Split up the harmonic motion 8 sin (ωt + π/4) into two harmonic motions one of which has amplitude of 10 and phase difference zero.

4.      A steel shaft 6 cm diameter and 50 cm long fixed at one end carries a flywheel of weight of 1000 kgf and radius of gyration 30cm at its free end. Find the frequency of free longitudinal transverse and torsional vibration E= 2 x 10⁶ kgf/ cm², C = 3.8 x 10⁶ kgf/ cm².

5.      A shock absorber is to be designed so that its overshoot is 10% of the initial displacement when released. Determine the damping factor. If the damping factor is reduced to one half this values, what will be the overshoot?

6.      A simple U tube manometer filled with liquid is ahown in figure 2. Calculate the frequency of resulting motion if the minimum length of a manometer tube is 0.15m.

Figure2

7.      A gun barrel having mass 560kg is designed with the following data: Initial recoil velocity 36 m/sec, recoil distance on firing 1.5 m

Calculate:

(a)    Spring constant

(b)   Damping coefficient

(c)    Time required for the barrel to return to a position 0.12 m from its initial position

8.      A vibratory system is defined by the following parameters:

m = 3kg, k = 100 N/m, C = 3 N- sec/m. Determine

a.      The damping factor

b.      The natural frequency of the damped vibration

c.       The logarithmic decrement

d.      The ratio of two consecutive amplitudes

The number of cycles after which the original amplitude is reduced to 20 percent.

Note: On the last date of submission of your assignment, a minor test of 20 marks will be conducted

Design of Machine Elements - I Assignmnet No I

Assignments No – I

Topic-Basic Machine Design, Design of Shaft, Keys & Coupling

Date of Issue: 8^th August, 2013                                                    Date of Submission: 14^th August, 2013

1.      Explain the different stages in the design of machine elements.

2.      A armature shaft of a 40 kW, 720 rpm electric motor, mounted on two bearings A and B as shown in figure. Total magnetic pull on the armature is 7 kN and it can be assumed to be uniformly distributed over a length of 700 mm midway between the bearings. The shaft is made of steel with a ultimate tensile strength of 770 N/mm² and yield strength of 580 N/mm².  Determine the diameter of shaft if K_m =1.5 and K_t=1.0, assume that the pulley is keyed to the shaft.

3.      The problem is shown in the given figure. A pulley drive is transmitting power to a pinion, which in turn is transmitting power to some other machine element. Pulley and pinion diameters are 400mm and 200mm respectively. Shaft has to be designed for minor to heavy shock

ASME code for shaft design is suitable in this case as no other specifications are provided.  In absence of any  data  for material  property,  the  allowable  shear  for  commercial  steel  shaft may  be  taken  as 40 MPa, where keyway is present in the shaft.  For the given condition of shock, let us consider K_m = 2.0 and K_t = 1.5.

4.      What is key? How are the keys classified? Draw neat sketches of different types of keys and state their applications.

5.      Discuss the function of couplings and effect of key way cut into shaft. Explain the difference between rigid and flexible coupling.

6.      Design a cast iron protective flange coupling to connect two shafts in order to transmit 7.5 kW at 720 rpm. The following permissible stresses may be used:

Permissible shear stress for shaft, bolt and key material = 33 MPa

Permissible crushing stress for bolt and key material = 60MPa

Permissible shear stress for the cat iron = 15 MPa

7.      Design  a  bushed  pin  type  flexible  coupling  for  connecting  a  motor  shaft  to  a  pump  shaft  for  the following service conditions:

Power to be transmitted = 40 kW; speed of the motor shaft = 1000 r.p.m.; diameter of the motor shaft = 50 mm; diameter of the pump shaft = 45 mm. The bearing pressure in the rubber bush and allowable stress in the pins are to be limited to 0.45 N/mm2 and 25 MPa respectively.

Note: On the last date of submission of your assignment, a minor test of 20 marks will be conducted